Find the Derivative - d/dx arccos(1/x)
Problem
Solution
Identify the outer function as
arccos(u) and the inner function asu=1/x Apply the chain rule, which states that
d(arccos(u))/d(x)=d(arccos(u))/d(u)⋅d(u)/d(x) Differentiate the outer function using the formula
d(arccos(u))/d(u)=−1/√(,1−u2) Differentiate the inner function
u=x(−1) using the power rule to getd(u)/d(x)=−x(−2)=−1/(x2) Substitute the expressions back into the chain rule formula.
Simplify the expression by multiplying the terms and simplifying the square root.
Distribute
x into the square root (noting√(,x2)=|x| to further simplify.
Final Answer
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