Find the Prime Factorization 225

Problem

225

Solution

1. Identify the smallest prime number that divides the given number. Since 225 is odd, it is not divisible by 2

2. Check for divisibility by 3 by summing the digits: 2 + 2 + 5 = 9.S*i*n*c*ei*s(d(i))*v*i*s(i)*b*l*e*b*y,25i*s(d(i))*v*i*s(i)*b*l*e*b*y$.

3. Divide 225 by 3

225÷3=75

4. Check 75 for divisibility by 3 again: 7 + 5 = 12.S*i*n*c*e2i*s(d(i))*v*i*s(i)*b*l*e*b*y,d(i)*v*i*d(e)5b*y$:

75÷3=25

5. Identify the next prime factor for 25 Since 2 + 5 = 7,i*t*i*s(n)*o*t*d(i)*v*i*s(i)*b*l*e*b*y.H*o*w*e*v*e*r,i*t*e*n*d(s(i))*n,s(o)*i*t*i*s(d(i))*v*i*s(i)*b*l*e*b*y$:

25÷5=5

6. Divide the remaining 5 by the prime number 5

5÷5=1

7. Write the prime factorization as a product of the prime factors found: 3×3×5×5

8. Express the product using exponents.

Final Answer

225=3⋅5

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