Write in Exponential Form log of x+ log of 8=2

Problem

(log_)(x)+(log_)(8)=2

Solution

1. Apply the product property of logarithms to combine the terms on the left side. Since (log_)(a)+(log_)(b)=(log_)(a*b) we multiply the arguments.

(log_)(8*x)=2

2. Identify the base of the logarithm. When no base is explicitly written for (log_)() it is assumed to be the common logarithm with base 10

(log_10)(8*x)=2

3. Convert to exponential form by using the definition of a logarithm: (log_b)(y)=x⇔bx=y

10=8*x

Final Answer

(log_)(x)+(log_)(8)=2⇒10=8*x

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