Write as a Vector Equality x-y^2=0 , (x+3)^2+y^2=53

Problem

{[x−y2=0],[(x+3)2+y2=53])

Solution

1. Identify the components of the vector equation by defining a vector x that contains the variables x and y

2. Define the vector function ƒ*(x) by moving all terms to one side of the equations so that the system takes the form ƒ*(x)=0

3. Construct the vector equality by grouping the left-hand side expressions into a single column vector and setting it equal to a zero vector or a constant vector.

4. Represent the system as a single vector equation where the vector of functions equals the vector of constants.

Final Answer

[[x−y2],[(x+3)2+y2]]=[[0],[53]]

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