Write as a Vector Equality x-2y+3z=20 , 2x+2y-z=22 , 3x+4y+6z=82

Problem

{[x−2*y+3*z=20],[2*x+2*y−z=22],[3*x+4*y+6*z=82])

Solution

1. Identify the coefficients of the variables x y and z for each equation in the system.

2. Represent the system as a linear combination of constant vectors scaled by the variables x y and z

3. Construct the vector equality by grouping the coefficients of each variable into column vectors and setting their sum equal to the vector of constants from the right-hand side.

Final Answer

x*[[1],[2],[3]]+y*[[−2],[2],[4]]+z*[[3],[−1],[6]]=[[20],[22],[82]]

Want more problems? Check here!