Write as a Vector Equality hj=2x+4 , jk=3x+3 , kh=22

Problem

h*j=2*x+4,j*k=3*x+3,k*h=22

Solution

1. Identify the vector loop property for a closed triangle formed by points h j and k

2. Apply the formula for the sum of vectors in a closed loop, which must equal the zero vector.

h*j+j*k+k*h=0

3. Substitute the given expressions for each vector into the equality.

(2*x+4)+(3*x+3)+22=0

4. Combine like terms to simplify the equation.

5*x+29=0

5. Solve for x by subtracting 29 from both sides and dividing by 5.

5*x=−29

x=−5.8

Final Answer

h*j+j*k+k*h=0⇒(2*x+4)+(3*x+3)+22=0

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