Write as a Vector Equality

Problem

{[x+y+u=k],[x2+y2+u2=k2−u],[1/x+1/y+1/u=1/6])

Solution

1. Define the vector of variables v and the vector of constants or functions ƒ

2. Represent the left-hand side of the system as a single vector L by grouping the expressions from each equation.

3. Represent the right-hand side of the system as a single vector R by grouping the corresponding values or expressions.

4. Equate the two vectors to form a single vector equality L=R

Final Answer

[[x+y+u],[x2+y2+u2],[1/x+1/y+1/u]]=[[k],[k2−u],[1/6]]

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