Write as a Vector Equality 6x+3y-3z=12 , 4x+2y-2z=8 , 3x+2y-z=8

Problem

{[6*x+3*y−3*z=12],[4*x+2*y−2*z=8],[3*x+2*y−z=8])

Solution

1. Identify the coefficients of the variables x y and z from each equation to form the coefficient matrix A

2. Define the vector of variables x as a column vector containing x y and z

3. Extract the constants from the right-hand side of each equation to form the constant vector b

4. Construct the vector equality by expressing the system in the form A*x=b

Final Answer

[[6,3,−3],[4,2,−2],[3,2,−1]]*[[x],[y],[z]]=[[12],[8],[8]]

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