Write as a Vector Equality 4s+3t=-9 , 1/3s+2=t

Problem

{[4*s+3*t=−9],[1/3*s+2=t])

Solution

1. Rearrange the second equation into standard form a*s+b*t=c by subtracting t from both sides and subtracting 2 from both sides.

1/3*s−t=−2

2. Identify the coefficients of the variables s() and t in both equations to form the vectors.

s*([4],[1/3])+t*([3],[−1])=([−9],[−2])

3. Verify the vector equality by performing scalar multiplication and vector addition to ensure it matches the original system.

([4*s()],[1/3*s()])+([3*t],[−t])=([−9],[−2])

Final Answer

s*([4],[1/3])+t*([3],[−1])=([−9],[−2])

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