Write as a Vector Equality 4a+2=5y-3 , y=3a-1

Problem

4*a+2=5*y−3,y=3*a−1

Solution

1. Rearrange the first equation to group the variables a and y on one side and the constants on the other.

4*a−5*y=−3−2

4*a−5*y=−5

2. Rearrange the second equation into the same standard form A*a+B*y=C

−3*a+y=−1

3. Identify the coefficients of the variables a and y to form a coefficient matrix and a vector of variables.

([4,−5],[−3,1])*([a],[y])

4. Identify the constants from the right side of both equations to form the constant vector.

([−5],[−1])

5. Equate the product of the coefficient matrix and the variable vector to the constant vector to form the vector equality.

([4,−5],[−3,1])*([a],[y])=([−5],[−1])

Final Answer

([4,−5],[−3,1])*([a],[y])=([−5],[−1])

Want more problems? Check here!