Simplify cube root of 8

Problem

$\sqrt[3]{8}$

Solution

1. Identify the number inside the radical, which is $8$

2. Factor the number into its prime components to find a perfect cube.

$8=2\cdot 2\cdot 2$

$8=2^3$

3. Apply the property of radicals where $\sqrt[n]{x^n}=x$ for any positive integer $n$

$\sqrt[3]{2^3}=2$

Final Answer

$\sqrt[3]{8}=2$

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