Solve Using the Quadratic Formula x^2-4x+29=0

Problem

x2−4*x+29=0

Solution

1. Identify the coefficients a b and c from the quadratic equation in the form a*x2+b*x+c=0

a=1

b=−4

c=29

2. Substitute these values into the quadratic formula.

x=(−b±√(,b2−4*a*c))/(2*a)

x=(−(−4)±√(,(−4)2−4*(1)*(29)))/(2*(1))

3. Simplify the expression inside the square root (the discriminant).

x=(4±√(,16−116))/2

x=(4±√(,−100))/2

4. Apply the imaginary unit i to handle the square root of the negative number, where √(,−100)=10*i

x=(4±10*i)/2

5. Divide each term in the numerator by the denominator to find the final solutions.

x=2±5*i

Final Answer

x=2±5*i

Want more problems? Check here!