Solve Using the Quadratic Formula x^2-14x+48=0

Problem

x2−14*x+48=0

Solution

1. Identify the coefficients a b and c from the quadratic equation in the form a*x2+b*x+c=0

a=1

b=−14

c=48

2. State the quadratic formula used to find the roots of the equation.

x=(−b±√(,b2−4*a*c))/(2*a)

3. Substitute the identified values into the quadratic formula.

x=(−(−14)±√(,(−14)2−4*(1)*(48)))/(2*(1))

4. Simplify the expression inside the square root (the discriminant).

x=(14±√(,196−192))/2

x=(14±√(,4))/2

5. Evaluate the square root and simplify the fraction to find the two possible values for x

x=(14±2)/2

6. Calculate the first solution using the plus sign.

x=(14+2)/2=16/2=8

7. Calculate the second solution using the minus sign.

x=(14−2)/2=12/2=6

Final Answer

x=6,8

Want more problems? Check here!