Solve Using the Quadratic Formula 7x^2+71x+72=0

Problem

7*x2+71*x+72=0

Solution

1. Identify the coefficients a b and c from the quadratic equation in the form a*x2+b*x+c=0

a=7

b=71

c=72

2. State the quadratic formula used to find the roots of the equation.

x=(−b±√(,b2−4*a*c))/(2*a)

3. Substitute the identified values into the quadratic formula.

x=(−71±√(,71−4*(7)*(72)))/(2*(7))

4. Simplify the expression inside the square root, which is the discriminant.

x=(−71±√(,5041−2016))/14

x=(−71±√(,3025))/14

5. Evaluate the square root of the discriminant.

x=(−71±55)/14

6. Solve for the two possible values of x by calculating both the addition and subtraction cases.

(x_1)=(−71+55)/14=(−16)/14=−8/7

(x_2)=(−71−55)/14=(−126)/14=−9

Final Answer

x=−8/7,−9

Want more problems? Check here!