Solve Using the Quadratic Formula 2x^2+18=0

Problem

2*x2+18=0

Solution

1. Identify the coefficients for the quadratic equation in the form a*x2+b*x+c=0

a=2

b=0

c=18

2. Apply the formula for the quadratic equation x=(−b±√(,b2−4*a*c))/(2*a)

x=(−0±√(,0−4*(2)*(18)))/(2*(2))

3. Simplify the expression inside the square root (the discriminant).

x=(±√(,−144))/4

4. Evaluate the square root of the negative number using the imaginary unit i where √(,−1)=i

x=(±12*i)/4

5. Divide to find the final values of x

x=±3*i

Final Answer

2*x2+18=0⇒x=±3*i

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