Solve Using the Quadratic Formula 2x^2-7x+5=0

Problem

2*x2−7*x+5=0

Solution

1. Identify the coefficients a b and c from the standard form a*x2+b*x+c=0

a=2

b=−7

c=5

2. State the quadratic formula.

x=(−b±√(,b2−4*a*c))/(2*a)

3. Substitute the values of a b and c into the formula.

x=(−(−7)±√(,(−7)2−4*(2)*(5)))/(2*(2))

4. Simplify the expression inside the square root (the discriminant).

x=(7±√(,49−40))/4

x=(7±√(,9))/4

5. Evaluate the square root.

x=(7±3)/4

6. Solve for the two possible values of x by calculating both the plus and minus cases.

(x_1)=(7+3)/4=10/4=5/2

(x_2)=(7−3)/4=4/4=1

Final Answer

x=5/2,1

Want more problems? Check here!