Solve for x 7 log base 4 of 0.6x=12

Problem

7*(log_4)(0.6*x)=12

Solution

1. Isolate the logarithmic expression by dividing both sides of the equation by 7

(log_4)(0.6*x)=12/7

2. Rewrite in exponential form by using the definition of a logarithm, where (log_b)(y)=a⇔ba=y

0.6*x=4

3. Isolate x by dividing both sides by 0.6 which is equivalent to 3/5

x=4/0.6

4. Simplify the expression by writing 0.6 as a fraction to find the exact value.

x=(5⋅4)/3

Final Answer

x=(5⋅4)/3

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