Solve for x 3x^2-4x-4=0

Problem

3*x2−4*x−4=0

Solution

1. Identify the coefficients of the quadratic equation in the form a*x2+b*x+c=0

a=3

b=−4

c=−4

2. Calculate the discriminant using the formula D=b2−4*a*c

D=(−4)2−4*(3)*(−4)

D=16+48

D=64

3. Apply the quadratic formula x=(−b±√(,D))/(2*a)

x=(−(−4)±√(,64))/(2*(3))

x=(4±8)/6

4. Solve for the two possible values of x by evaluating the plus and minus cases.

(x_1)=(4+8)/6=12/6=2

(x_2)=(4−8)/6=(−4)/6=−2/3

Final Answer

x=2,−2/3

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