Solve for x 2x^2-2.10x-0.48=0

Problem

2*x2−2.10*x−0.48=0

Solution

1. Identify the coefficients of the quadratic equation in the form a*x2+b*x+c=0

a=2

b=−2.10

c=−0.48

2. Apply the quadratic formula to find the values of x

x=(−b±√(,b2−4*a*c))/(2*a)

3. Substitute the values of a b and c into the formula.

x=(−(−2.10)±√(,(−2.10)2−4*(2)*(−0.48)))/(2*(2))

4. Simplify the expression inside the square root (the discriminant).

x=(2.10±√(,4.41+3.84))/4

x=(2.10±√(,8.25))/4

5. Calculate the square root of 8.25

√(,8.25)≈2.87228

6. Solve for both possible values of x

(x_1)=(2.10+2.87228)/4=4.97228/4=1.24307

(x_2)=(2.10−2.87228)/4=(−0.77228)/4=−0.19307

Final Answer

x=1.24307,−0.19307

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