Solve for b 8^2+b^2=17^2

Problem

8+b2=17

Solution

1. Evaluate the squares of the known constants in the equation.

8=64

17=289

2. Substitute these values back into the original equation.

64+b2=289

3. Isolate the term containing b by subtracting 64 from both sides of the equation.

b2=289−64

b2=225

4. Solve for b by taking the square root of both sides.

b=√(,225)

b=15

Final Answer

b=15

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