Solve for a h=bt+1/2*(at^2)

Problem

h=b*t+1/2*a*t2

Solution

1. Subtract the term b*t from both sides of the equation to isolate the term containing a

h−b*t=1/2*a*t2

2. Multiply both sides by 2 to eliminate the fraction.

2*(h−b*t)=a*t2

3. Divide both sides by t2 to solve for a assuming t≠0

a=(2*(h−b*t))/(t2)

4. Distribute the 2 in the numerator to simplify the expression.

a=(2*h−2*b*t)/(t2)

Final Answer

a=(2*(h−b*t))/(t2)

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