Solve by Substitution 4x+3y+7=0 , 5x-2y+3=0

Problem

{[4*x+3*y+7=0],[5*x−2*y+3=0])

Solution

1. Solve the first equation for y to prepare for substitution.

4*x+3*y+7=0

3*y=−4*x−7

y=(−4*x−7)/3

2. Substitute the expression for y into the second equation.

5*x−2*((−4*x−7)/3)+3=0

3. Multiply the entire equation by 3 to eliminate the fraction.

15*x−2*(−4*x−7)+9=0

4. Distribute the constant and combine like terms.

15*x+8*x+14+9=0

23*x+23=0

5. Solve for x

23*x=−23

x=−1

6. Substitute the value of x back into the expression for y

y=(−4*(−1)−7)/3

y=(4−7)/3

y=(−3)/3

y=−1

Final Answer

(x,y)=(−1,−1)

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