Solve by Substitution 3x+7y+2=0 , 12x+28y-6=0

Problem

{[3*x+7*y+2=0],[12*x+28*y−6=0])

Solution

1. Isolate a variable in the first equation. We will solve for 3*x to make the substitution into the second equation easier.

3*x=−7*y−2

2. Substitute the expression for 3*x into the second equation. Notice that 12*x is 4*(3*x)

4*(3*x)+28*y−6=0

4*(−7*y−2)+28*y−6=0

3. Distribute the constant into the parentheses.

−28*y−8+28*y−6=0

4. Combine like terms to simplify the equation.

−28*y+28*y−14=0

−14=0

5. Interpret the result. Since the variables have been eliminated and the resulting statement −14=0 is false, the system of equations is inconsistent.

Final Answer

No solution

Want more problems? Check here!