Solve by Substitution 11x-20y=28 , 3x+4y=36

Problem

{[11*x−20*y=28],[3*x+4*y=36])

Solution

1. Isolate a variable in one of the equations. We will solve the second equation for y

3*x+4*y=36

4*y=36−3*x

y=9−3/4*x

2. Substitute the expression for y into the first equation:

11*x−20*(9−3/4*x)=28

3. Distribute the constant and simplify the equation:

11*x−180+15*x=28

26*x−180=28

4. Solve for x by isolating the variable:

26*x=208

x=8

5. Substitute the value of x back into the expression for y

y=9−3/4*(8)

y=9−6

y=3

Final Answer

(x,y)=(8,3)

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