Simplify the Matrix
Problem
[[−1/√(,2),−1/√(,2),1/√(,3)],[1/√(,2),0,1/√(,3)],[0,1/√(,2),1/√(,3)]]*[[1,0,0],[0,1,0],[0,0,4]]*[[−1/√(,2),1/√(,2),0],[−1/√(,2),0,1/√(,2)],[1/√(,3),1/√(,3),1/√(,3)]]
Solution
Multiply the first matrix by the diagonal matrix. Since the second matrix is diagonal, each column of the first matrix is scaled by the corresponding diagonal entry.
[[−1/√(,2),−1/√(,2),1/√(,3)],[1/√(,2),0,1/√(,3)],[0,1/√(,2),1/√(,3)]]*[[1,0,0],[0,1,0],[0,0,4]]=[[−1/√(,2),−1/√(,2),4/√(,3)],[1/√(,2),0,4/√(,3)],[0,1/√(,2),4/√(,3)]]
Multiply the resulting matrix by the third matrix. Calculate the entry at row 1, column 1.
(−1/√(,2))*(−1/√(,2))+(−1/√(,2))*(−1/√(,2))+(4/√(,3))*(1/√(,3))=1/2+1/2+4/3=7/3
Calculate the entry at row 1, column 2.
(−1/√(,2))*(1/√(,2))+(−1/√(,2))*(0)+(4/√(,3))*(1/√(,3))=−1/2+0+4/3=5/6
Calculate the entry at row 1, column 3.
(−1/√(,2))*(0)+(−1/√(,2))*(1/√(,2))+(4/√(,3))*(1/√(,3))=0−1/2+4/3=5/6
Calculate the entry at row 2, column 1.
(1/√(,2))*(−1/√(,2))+(0)*(−1/√(,2))+(4/√(,3))*(1/√(,3))=−1/2+0+4/3=5/6
Calculate the entry at row 2, column 2.
(1/√(,2))*(1/√(,2))+(0)*(0)+(4/√(,3))*(1/√(,3))=1/2+0+4/3=11/6
Calculate the entry at row 2, column 3.
(1/√(,2))*(0)+(0)*(1/√(,2))+(4/√(,3))*(1/√(,3))=0+0+4/3=4/3
Calculate the entry at row 3, column 1.
(0)*(−1/√(,2))+(1/√(,2))*(−1/√(,2))+(4/√(,3))*(1/√(,3))=0−1/2+4/3=5/6
Calculate the entry at row 3, column 2.
(0)*(1/√(,2))+(1/√(,2))*(0)+(4/√(,3))*(1/√(,3))=0+0+4/3=4/3
Calculate the entry at row 3, column 3.
(0)*(0)+(1/√(,2))*(1/√(,2))+(4/√(,3))*(1/√(,3))=0+1/2+4/3=11/6
Final Answer
[[−1/√(,2),−1/√(,2),1/√(,3)],[1/√(,2),0,1/√(,3)],[0,1/√(,2),1/√(,3)]]*[[1,0,0],[0,1,0],[0,0,4]]*[[−1/√(,2),1/√(,2),0],[−1/√(,2),0,1/√(,2)],[1/√(,3),1/√(,3),1/√(,3)]]=[[7/3,5/6,5/6],[5/6,11/6,4/3],[5/6,4/3,11/6]]
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