Simplify the Matrix
Problem
Solution
Eliminate the first entry of the third row by adding the first row to the third row (
(R_3)←(R_3)+(R_1) .
Eliminate the first entry of the second row by multiplying the second row by 3 and subtracting 2 times the first row (
(R_2)←3*(R_2)−2*(R_1) .
Swap the second and third rows to make calculations easier (
(R_2)↔(R_3) .
Eliminate the second entry of the third row by subtracting 15 times the second row from the third row (
(R_3)←(R_3)−15*(R_2) .
Scale the third row by dividing by
−79 ((R_3)←(R_3)/(−79) .
Eliminate the third entries of the first and second rows using the third row (
(R_2)←(R_2)−4*(R_3) and(R_1)←(R_1)+4*(R_3) .
Eliminate the second entry of the first row by adding 6 times the second row to the first row (
(R_1)←(R_1)+6*(R_2) .
Scale the first and second rows to obtain the reduced row echelon form (
(R_1)←(R_1)/3 and(R_2)←−(R_2) .
Final Answer
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