Simplify the Matrix 3[[1,3],[4,2]]-[[3,3],[4,4]]

Problem

3*[[1,3],[4,2]]−[[3,3],[4,4]]

Solution

1. Perform scalar multiplication by multiplying every element in the first matrix by 3.

3*[[1,3],[4,2]]=[[3*(1),3*(3)],[3*(4),3*(2)]]

[[3*(1),3*(3)],[3*(4),3*(2)]]=[[3,9],[12,6]]

2. Subtract the second matrix from the result by subtracting corresponding elements.

[[3,9],[12,6]]−[[3,3],[4,4]]=[[3−3,9−3],[12−4,6−4]]

3. Simplify the arithmetic within each position of the matrix to find the final values.

[[3−3,9−3],[12−4,6−4]]=[[0,6],[8,2]]

Final Answer

3*[[1,3],[4,2]]−[[3,3],[4,4]]=[[0,6],[8,2]]

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