Simplify sin(3x-2pi)

Problem

sin(3*x−2*π)

Solution

1. Identify the periodicity of the sine function, which states that sin(θ+2*π*k)=sin(θ) for any integer k

2. Apply the property by letting θ=3*x and k=−1

3. Simplify the expression using the identity sin(3*x−2*π)=sin(3*x)

Final Answer

sin(3*x−2*π)=sin(3*x)

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