Simplify cube root of 27

Problem

√(3,27)

Solution

1. Identify the number inside the radical, which is 27

2. Find the prime factorization of the radicand to see if it is a perfect cube.

27=3⋅3⋅3

3. Rewrite the expression using an exponent to represent the repeated multiplication.

27=3

4. Apply the property of radicals where √(n,an)=a for any positive integer n

√(3,3)=3

Final Answer

√(3,27)=3

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