Simplify cos(arcsin(-( square root of 3)/2))
Problem
Solution
Identify the inner value
y=arcsin(−√(,3)/2) This represents the angle in the interval[−π/2,π/2] whose sine is−√(,3)/2 Evaluate the inverse sine function. Since
sin(π/3)=√(,3)/2 and the sine function is odd,sin(−π/3)=−√(,3)/2 Substitute the angle back into the outer cosine function. We now need to find
cos(−π/3) Apply the property that cosine is an even function, meaning
cos(−θ)=cos(θ) Simplify the expression using the known value
cos(π/3)=1/2
Final Answer
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