Simplify cos(arcsin(4/5))
Problem
Solution
Identify the inner expression as an angle
θ=arcsin(4/5) which impliessin(θ)=4/5 whereθ is in the interval[−π/2,π/2] Use the Pythagorean identity
sin2(θ)+cos2(θ)=1 to find the value ofcos(θ) Substitute the known value of
sin(θ) into the identity:(4/5)2+cos2(θ)=1 Solve for
cos2(θ) by calculating1 - 16/25 = 9/25$.Determine the sign of
cos(θ) by noting that forθ=arcsin(4/5) the angle is in the first quadrant, socos(θ) must be positive.Calculate the square root:
cos(θ)=√(,9/25)=3/5
Final Answer
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