Simplify arcsin((- square root of 3)/2)
Problem
Solution
Identify the range of the inverse sine function, which is
[−π/2,π/2] Recall the property of the inverse sine function for negative values, which states
arcsin(−x)=−arcsin(x) Apply the property to rewrite the expression as
−arcsin(√(,3)/2) Determine the angle
θ in the interval[0,π/2] such thatsin(θ)=√(,3)/2 Evaluate the value using known trigonometric values, where
sin(π/3)=√(,3)/2 Combine the results to find the final value.
Final Answer
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