Multiply the Matrices

Problem

1/(2*a)*[[2,−8,−10,−14],[−2,3,1,0],[7,0,−1,−3]]

Solution

1. Identify the scalar multiplication operation, where every entry in the 3×4 matrix must be multiplied by the scalar 1/(2*a)

2. Distribute the scalar to each element in the first row: 2⋅1/(2*a)=1/a −8⋅1/(2*a)=−4/a −10⋅1/(2*a)=−5/a and −14⋅1/(2*a)=−7/a

3. Distribute the scalar to each element in the second row: −2⋅1/(2*a)=−1/a 3⋅1/(2*a)=3/(2*a) 1⋅1/(2*a)=1/(2*a) and 0⋅1/(2*a)=0

4. Distribute the scalar to each element in the third row: 7⋅1/(2*a)=7/(2*a) 0⋅1/(2*a)=0 −1⋅1/(2*a)=−1/(2*a) and −3⋅1/(2*a)=−3/(2*a)

Final Answer

1/(2*a)*[[2,−8,−10,−14],[−2,3,1,0],[7,0,−1,−3]]=[[1/a,−4/a,−5/a,−7/a],[−1/a,3/(2*a),1/(2*a),0],[7/(2*a),0,−1/(2*a),−3/(2*a)]]

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