Multiply (3x+7)*(7x-3)

Problem

(3*x+7)*(7*x−3)

Solution

1. Apply the FOIL method to multiply the two binomials by distributing each term in the first expression to each term in the second expression.

2. Multiply the First terms of each binomial: 3*x⋅7*x

3*x⋅7*x=21*x2

3. Multiply the Outer terms of the binomials: 3*x⋅(−3)

3*x⋅(−3)=−9*x

4. Multiply the Inner terms of the binomials: 7⋅7*x

7⋅7*x=49*x

5. Multiply the Last terms of each binomial: 7⋅(−3)

7⋅(−3)=−21

6. Combine like terms by adding the results of the outer and inner products.

−9*x+49*x=40*x

7. Write the final expression by combining all the calculated terms.

21*x2+40*x−21

Final Answer

(3*x+7)*(7*x−3)=21*x2+40*x−21

Want more problems? Check here!