Solve for x 0=0.0241x^2x+5.5

Problem

0=0.0241*x^2+x+5.5

Solution

1. Identify the equation as a quadratic equation in the form a*x^2+b*x+c=0 where a=0.0241 b=1 and c=5.5

2. Apply the quadratic formula x=(−b±√(,b^2−4*a*c))/(2*a) to find the roots of the equation.

3. Calculate the discriminant D=b^2−4*a*c to determine the nature of the roots.

D=1^2−4*(0.0241)*(5.5)

D=1−0.5302

D=0.4698

4. Substitute the values back into the quadratic formula.

x=(−1±√(,0.4698))/(2*(0.0241))

x=(−1±0.6854195795...)/0.0482

5. Solve for the two possible values of x by calculating both the addition and subtraction cases.

(x_1)=(−1+0.6854195795)/0.0482≈−6.52656

(x_2)=(−1−0.6854195795)/0.0482≈−34.96721

Final Answer

x≈−6.5266,−34.9672

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