Simplify square root of 507

Problem

√(,507)

Solution

1. Identify the prime factors of the number under the radical.

2. Check for divisibility by small primes. Since the sum of the digits 5 + 0 + 7 = 12i*s(d(i))*v*i*s(i)*b*l*e*b*y,t*h*e*n*u*m*b*e*r07i*s(d(i))*v*i*s(i)*b*l*e*b*y$.

3. Divide 507 by 3 to find the other factor.

507=3×169

4. Recognize that 169 is a perfect square.

169=13

5. Rewrite the original expression using these factors.

√(,507)=√(,3×13)

6. Apply the product property of radicals √(,a×b)=√(,a)×√(,b) to simplify.

√(,3×13)=13√(,3)

Final Answer

√(,507)=13√(,3)

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