Find the Derivative - d/dx f(x) = square root of x^2+1
Problem
Solution
Identify the function as a composition of functions where the outer function is the square root,
u(1/2) and the inner function isu=x2+1 Apply the power rule and the chain rule, which states that
d(√(,u))/d(x)=1/(2√(,u))⋅d(u)/d(x) Differentiate the inner function
x2+1 with respect tox to get2*x Substitute the inner function and its derivative back into the chain rule formula:
1/(2√(,x2+1))⋅2*x Simplify the expression by canceling the factor of
2 in the numerator and denominator.
Final Answer
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