Factor 9x^2-6x+1

Problem

9*x2−6*x+1

Solution

1. Identify the structure of the quadratic expression, which is in the form a*x2+b*x+c where a=9 b=−6 and c=1

2. Recognize that the first term 9*x2 is a perfect square (3*x)2 and the last term 1 is a perfect square (1)2

3. Check if the middle term fits the pattern for a perfect square trinomial a2−2*a*b+b2=(a−b)2

4. Verify the middle term by calculating 2(3x)(1) = 6x,w*h*i*c*h*m*a*t*c*h*e*s(t)*h*e*m*a*g*n*i*t*u*d(e)*o*ƒ*t*h*e*g*i*v*e*n*m*i*d(d(l))*e*t*e*r*m6x$.

5. Apply the perfect square trinomial formula (A−B)2=A2−2*A*B+B2 where A=3*x and B=1

Final Answer

9*x2−6*x+1=(3*x−1)2

Want more problems? Check here!