Graph y=x^2-10

Problem

y=x2−10

Solution

1. Identify the type of function. This is a quadratic function in the form y=a*x2+c which represents a parabola.

2. Determine the vertex. Since there is no x term (b=0, the xcoordinate of the vertex is 0 Substituting x=0 into the equation gives y=−10 The vertex is (0,−10)

3. Find the y-intercept. Setting x=0 results in y=−10

4. Find the x-intercepts. Set y=0 and solve x2−10=0 which gives x=±√(,10) or approximately ±3.16

5. Determine the opening direction. Since the coefficient of x2 is positive (a=1, the parabola opens upward.

6. Plot additional points to define the shape. For x=±1 y=−9 For x=±2 y=−6 For x=±4 y=6

7. Sketch the curve. Draw a smooth U-shaped curve passing through the vertex (0,−10) and the calculated points.

Final Answer

y=x2−10

Want more problems? Check here!