Graph y=(x+3)^2
Problem
Solution
Identify the type of function. This is a quadratic function in vertex form
y=a*(x−h)2+k wherea=1 h=−3 andk=0 Determine the vertex. The vertex
(h,k) is located at(−3,0) Find the y-intercept. Set
x=0 to findy=(0+3)2=9 The y-intercept is(0,9) Identify the axis of symmetry. The vertical line passing through the vertex is
x=−3 Plot additional points to define the shape. For
x=−2 y=(−2+3)2=1 Forx=−4 y=(−4+3)2=1 Sketch the parabola. Draw a smooth U-shaped curve opening upwards through the points
(−3,0) (−2,1) (−4,1) and(0,9)
Final Answer
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