Graph y=(x+2)^2

Problem

y=(x+2)2

Solution

1. Identify the type of function. This is a quadratic function in vertex form y=a*(x−h)2+k where a=1 h=−2 and k=0

2. Determine the vertex. The vertex (h,k) is located at (−2,0)

3. Find the y-intercept. Set x=0 to get y=(0+2)2=4 The y-intercept is (0,4)

4. Identify the axis of symmetry. The vertical line passing through the vertex is x=−2

5. Calculate additional points to define the shape. For x=−1 y=(−1+2)2=1 For x=−3 y=(−3+2)2=1

6. Plot the vertex (−2,0) the y-intercept (0,4) and the points (−1,1) and (−3,1) then draw a smooth upward-opening parabola.

Final Answer

y=(x+2)2

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