Graph y=(x-3)^2
Problem
Solution
Identify the type of function. This is a quadratic function in vertex form
y=a*(x−h)2+k wherea=1 h=3 andk=0 Determine the vertex. The vertex
(h,k) is(3,0) Find the axis of symmetry. The vertical line passing through the vertex is
x=3 Calculate the y-intercept. Set
x=0 to findy=(0−3)2=9 The y-intercept is(0,9) Select additional points to plot. For
x=2 y=(2−3)2=1 Forx=4 y=(4−3)2=1 Sketch the parabola. Plot the points
(3,0) (0,9) (2,1) and(4,1) then draw a smooth U-shaped curve opening upward.
Final Answer
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