Graph y=-6sin(x)
Problem
Solution
Identify the parent function and its properties. The base function is
y=sin(x) which has a period of2*π an amplitude of1 and passes through the origin(0,0) Determine the amplitude of the given function. For
y=a*sin(b*x) the amplitude is|a| Here,a=−6 so the amplitude is|−6|=6 This means the graph will oscillate betweeny=6 andy=−6 Identify the reflection across the x-axis. Since the coefficient
a is negative (a=−6 , the graph ofsin(x) is reflected vertically. Instead of starting by moving upward from the origin, the graph will move downward.Determine the period of the function. The coefficient of
x isb=1 The period is calculated as(2*π)/|b| which results in(2*π)/1=2*π Find the key points for one cycle. Divide the period into four equal intervals of
π/2
At
x=0 y=−6*sin(0)=0 At
x=π/2 y=−6*sin(π/2)=−6 At
x=π y=−6*sin(π)=0 At
x=(3*π)/2 y=−6*sin((3*π)/2)=6 At
x=2*π y=−6*sin(2*π)=0
Plot the points and draw a smooth wave. Connect the coordinates
(0,0) (π/2,−6) (π,0) ((3*π)/2,6) and(2*π,0) to complete one period of the sine wave.
Final Answer
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