Graph y=4x^2
Problem
Solution
Identify the type of function. This is a quadratic function in the form
y=a*x2 which represents a parabola.Determine the vertex. Since there are no horizontal or vertical shifts, the vertex is at the origin
(0,0) Analyze the opening direction and width. Because the coefficient
a=4 is positive, the parabola opens upward. Since|a|>1 the graph is narrower (vertically stretched) compared to the parent functiony=x2 Calculate additional points to define the shape.
If
x=1 y=4*(1)2=4 Point:(1,4) If
x=−1 y=4*(−1)2=4 Point:(−1,4) If
x=2 y=4*(2)2=16 Point:(2,16)
Plot the vertex
(0,0) and the calculated points, then draw a smooth U-shaped curve through them.
Final Answer
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