Graph y=2 square root of x

Problem

y=2√(,x)

Solution

1. Identify the domain of the function. Since the square root of a negative number is not a real number, we must have x≥0

2. Determine the starting point by substituting the smallest value in the domain. When x=0 y=2√(,0)=0 The graph starts at the origin (0,0)

3. Calculate key points to determine the shape and steepness of the curve.

• If x=1 y=2√(,1)=2 Point: (1,2)

• If x=4 y=2√(,4)=2*(2)=4 Point: (4,4)

• If x=9 y=2√(,9)=2*(3)=6 Point: (9,6)

4. Analyze the transformation of the parent function ƒ(x)=√(,x) The coefficient 2 represents a vertical stretch by a factor of 2

5. Sketch the curve starting from (0,0) and passing through the calculated points (1,2) (4,4) and (9,6) extending to the right in a smooth, increasing arc.

Final Answer

y=2√(,x)

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