Graph x^2+y^2=36
Problem
Solution
Identify the type of equation. The equation
x2+y2=36 is in the standard form of a circle centered at the origin, which isx2+y2=r2 Determine the center of the circle. Since there are no horizontal or vertical shifts (no
h ork values subtracted fromx ory , the center is at(0,0) Calculate the radius. The constant on the right side represents
r2
Plot the key points. Starting from the center
(0,0) move6 units in each cardinal direction to find the intercepts:(6,0) (−6,0) (0,6) and(0,−6) Sketch the graph. Draw a smooth curve connecting these four points to form a circle with a radius of
6
Final Answer
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