Graph x^2+4
Problem
Solution
Identify the type of function. This is a quadratic function in the form
y=a*x2+c which represents a parabola.Determine the vertex. Since there is no
x term (b=0 , the vertex is located on they axis at(0,4) Determine the direction of opening. Because the coefficient of
x2 is positive (a=1 , the parabola opens upward.Find additional points to define the shape. For
x=1 andx=−1 y=1+4=5 Forx=2 andx=−2 y=2+4=8 Sketch the curve. Plot the vertex
(0,4) and the points(−2,8) (−1,5) (1,5) and(2,8) then connect them with a smooth, U-shaped curve.
Final Answer
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