Graph x^2=9y
Problem
Solution
Identify the type of conic section. The equation is in the form
x2=4*p*y which represents a parabola that opens vertically.Determine the vertex. Since there are no
h ork offsets in the equation, the vertex is at the origin(0,0) Find the value of
p Set the coefficient ofy equal to4*p
Locate the focus and directrix. Since
p is positive and the parabola opens upward, the focus is at(0,p) and the directrix is the horizontal liney=−p
Calculate additional points to define the width. Choose
y values that makex easy to calculate, such asy=1 andy=4
Sketch the graph by plotting the vertex
(0,0) the points(3,1) (−3,1) (6,4) and(−6,4) and drawing a smooth upward-opening curve through them.
Final Answer
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