Graph x^2
Problem
Solution
Identify the function as a basic quadratic equation of the form
y=a*x2+b*x+c wherea=1 b=0 andc=0 Determine the shape of the graph, which is a parabola that opens upward because the leading coefficient
a is positive.Locate the vertex by using the formula
x=(−b)/(2*a) which givesx=0 Substitutingx=0 into the function yieldsy=0 so the vertex is at(0,0) Calculate additional points to define the curve, such as
(±1,1) and(±2,4) Sketch the smooth, U-shaped curve passing through these points, symmetric about the y-axis (
x=0 .
Final Answer
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