Graph x^2-5

Problem

y=x2−5

Solution

1. Identify the type of function, which is a quadratic function in the form y=a*x2+b*x+c

2. Determine the vertex of the parabola. Since b=0 the xcoordinate of the vertex is x=0

3. Calculate the ycoordinate of the vertex by substituting x=0 into the equation, giving y=−5 The vertex is (0,−5)

4. Find the yintercept by setting x=0 which is (0,−5)

5. Find the xintercepts by setting y=0 and solving x2−5=0 which gives x=±√(,5)≈±2.24

6. Plot additional points to determine the shape, such as (±1,−4) and (±2,−1)

7. Sketch the graph as an upward-opening parabola with its lowest point at the vertex (0,−5)

Final Answer

y=x2−5

Want more problems? Check here!